0=5x^2-200-5

Solution for 0=5x^2-200-5 equation:

0=5x^2-200-5

We move all terms to the left:

0-(5x^2-200-5)=0

We add all the numbers together, and all the variables

-(5x^2-200-5)=0

We get rid of parentheses

-5x^2+200+5=0

We add all the numbers together, and all the variables

-5x^2+205=0

a = -5; b = 0; c = +205;
Δ = b2-4ac
Δ = 02-4·(-5)·205
Δ = 4100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4100}=\sqrt{100*41}=\sqrt{100}*\sqrt{41}=10\sqrt{41}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{41}}{2*-5}=\frac{0-10\sqrt{41}}{-10}
=-\frac{10\sqrt{41}}{-10}
=-\frac{\sqrt{41}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{41}}{2*-5}=\frac{0+10\sqrt{41}}{-10}
=\frac{10\sqrt{41}}{-10}
=\frac{\sqrt{41}}{-1}
$